8(8x+1)=2(x-2)

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Solution for 8(8x+1)=2(x-2) equation: 



8(8x+1)=2(x-2)

We move all terms to the left:

8(8x+1)-(2(x-2))=0

We multiply parentheses

64x-(2(x-2))+8=0



We calculate terms in parentheses: -(2(x-2)), so:

2(x-2)

We multiply parentheses

2x-4

Back to the equation:

-(2x-4)



We get rid of parentheses

64x-2x+4+8=0

We add all the numbers together, and all the variables

62x+12=0

We move all terms containing x to the left, all other terms to the right

62x=-12

x=-12/62

x=-6/31

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