8(9+c)=7(c-1)

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Solution for 8(9+c)=7(c-1) equation: 



8(9+c)=7(c-1)

We move all terms to the left:

8(9+c)-(7(c-1))=0

We add all the numbers together, and all the variables

8(c+9)-(7(c-1))=0

We multiply parentheses

8c-(7(c-1))+72=0



We calculate terms in parentheses: -(7(c-1)), so:

7(c-1)

We multiply parentheses

7c-7

Back to the equation:

-(7c-7)



We get rid of parentheses

8c-7c+7+72=0

We add all the numbers together, and all the variables

c+79=0

We move all terms containing c to the left, all other terms to the right

c=-79

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