8(9-x)+12=648(9-x)+12=64

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Solution for 8(9-x)+12=648(9-x)+12=64 equation: 



8(9-x)+12=648(9-x)+12=64

We move all terms to the left:

8(9-x)+12-(648(9-x)+12)=0

We add all the numbers together, and all the variables

8(-1x+9)-(648(-1x+9)+12)+12=0

We multiply parentheses

-8x-(648(-1x+9)+12)+72+12=0



We calculate terms in parentheses: -(648(-1x+9)+12), so:

648(-1x+9)+12

We multiply parentheses

-648x+5832+12

We add all the numbers together, and all the variables

-648x+5844

Back to the equation:

-(-648x+5844)



We add all the numbers together, and all the variables

-8x-(-648x+5844)+84=0

We get rid of parentheses

-8x+648x-5844+84=0

We add all the numbers together, and all the variables

640x-5760=0

We move all terms containing x to the left, all other terms to the right

640x=5760

x=5760/640

x=9

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