8(9x+3)-4+8x=7(3x+4)+39x-3

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Solution for 8(9x+3)-4+8x=7(3x+4)+39x-3 equation: 



8(9x+3)-4+8x=7(3x+4)+39x-3

We move all terms to the left:

8(9x+3)-4+8x-(7(3x+4)+39x-3)=0

We add all the numbers together, and all the variables

8x+8(9x+3)-(7(3x+4)+39x-3)-4=0

We multiply parentheses

8x+72x-(7(3x+4)+39x-3)+24-4=0



We calculate terms in parentheses: -(7(3x+4)+39x-3), so:

7(3x+4)+39x-3

We add all the numbers together, and all the variables

39x+7(3x+4)-3

We multiply parentheses

39x+21x+28-3

We add all the numbers together, and all the variables

60x+25

Back to the equation:

-(60x+25)



We add all the numbers together, and all the variables

80x-(60x+25)+20=0

We get rid of parentheses

80x-60x-25+20=0

We add all the numbers together, and all the variables

20x-5=0

We move all terms containing x to the left, all other terms to the right

20x=5

x=5/20

x=1/4

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