8(X+1)+3(6-x)=4(X+10)

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Solution for 8(X+1)+3(6-x)=4(X+10) equation: 



8(X+1)+3(6-X)=4(X+10)

We move all terms to the left:

8(X+1)+3(6-X)-(4(X+10))=0

We add all the numbers together, and all the variables

8(X+1)+3(-1X+6)-(4(X+10))=0

We multiply parentheses

8X-3X-(4(X+10))+8+18=0



We calculate terms in parentheses: -(4(X+10)), so:

4(X+10)

We multiply parentheses

4X+40

Back to the equation:

-(4X+40)



We add all the numbers together, and all the variables

5X-(4X+40)+26=0

We get rid of parentheses

5X-4X-40+26=0

We add all the numbers together, and all the variables

X-14=0

We move all terms containing X to the left, all other terms to the right

X=14

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