8(a+1)+2a=48+3a-5

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Solution for 8(a+1)+2a=48+3a-5 equation:



8(a+1)+2a=48+3a-5
We move all terms to the left:
8(a+1)+2a-(48+3a-5)=0
We add all the numbers together, and all the variables
8(a+1)+2a-(3a+43)=0
We add all the numbers together, and all the variables
2a+8(a+1)-(3a+43)=0
We multiply parentheses
2a+8a-(3a+43)+8=0
We get rid of parentheses
2a+8a-3a-43+8=0
We add all the numbers together, and all the variables
7a-35=0
We move all terms containing a to the left, all other terms to the right
7a=35
a=35/7
a=5

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