8(a-4)=5(a+5)a=

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Solution for 8(a-4)=5(a+5)a= equation: 



8(a-4)=5(a+5)a=

We move all terms to the left:

8(a-4)-(5(a+5)a)=0

We multiply parentheses

8a-(5(a+5)a)-32=0



We calculate terms in parentheses: -(5(a+5)a), so:

5(a+5)a

We multiply parentheses

5a^2+25a

Back to the equation:

-(5a^2+25a)



We get rid of parentheses

-5a^2+8a-25a-32=0

We add all the numbers together, and all the variables

-5a^2-17a-32=0

a = -5; b = -17; c = -32;
Δ = b2-4ac
Δ = -172-4·(-5)·(-32)
Δ = -351
Delta is less than zero, so there is no solution for the equation

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