8(b+1)+4=(2b-8)-16

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Solution for 8(b+1)+4=(2b-8)-16 equation: 



8(b+1)+4=(2b-8)-16

We move all terms to the left:

8(b+1)+4-((2b-8)-16)=0

We multiply parentheses

8b-((2b-8)-16)+8+4=0



We calculate terms in parentheses: -((2b-8)-16), so:

(2b-8)-16

We get rid of parentheses

2b-8-16

We add all the numbers together, and all the variables

2b-24

Back to the equation:

-(2b-24)



We add all the numbers together, and all the variables

8b-(2b-24)+12=0

We get rid of parentheses

8b-2b+24+12=0

We add all the numbers together, and all the variables

6b+36=0

We move all terms containing b to the left, all other terms to the right

6b=-36

b=-36/6

b=-6

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