8(b+1)+4=-2/3(-9b+36)-16

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Solution for 8(b+1)+4=-2/3(-9b+36)-16 equation: 



8(b+1)+4=-2/3(-9b+36)-16

We move all terms to the left:

8(b+1)+4-(-2/3(-9b+36)-16)=0



Domain of the equation: 3(-9b+36)-16)!=0

b∈R



We multiply parentheses

8b-(-2/3(-9b+36)-16)+8+4=0

We multiply all the terms by the denominator


8b*3(-9b+36)+8*3(-9b+36)-9b-2-16)-(-16)+4*3(+36)-16)=0

We add all the numbers together, and all the variables

8b*3(-9b+36)+8*3(-9b+36)-9b-2-16)-(-16)+4*336-16)=0

We add all the numbers together, and all the variables

-9b+8b*3(-9b+36)+8*3(-9b+36)=0

Wy multiply elements

24b^2(-+24b(--9b=0

We use the square of the difference formula

24b^2(-24b(+9b=0

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