8(b+1)+4=3(2b+8)+16

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Solution for 8(b+1)+4=3(2b+8)+16 equation:


Simplifying
8(b + 1) + 4 = 3(2b + 8) + 16

Reorder the terms:
8(1 + b) + 4 = 3(2b + 8) + 16
(1 * 8 + b * 8) + 4 = 3(2b + 8) + 16
(8 + 8b) + 4 = 3(2b + 8) + 16

Reorder the terms:
8 + 4 + 8b = 3(2b + 8) + 16

Combine like terms: 8 + 4 = 12
12 + 8b = 3(2b + 8) + 16

Reorder the terms:
12 + 8b = 3(8 + 2b) + 16
12 + 8b = (8 * 3 + 2b * 3) + 16
12 + 8b = (24 + 6b) + 16

Reorder the terms:
12 + 8b = 24 + 16 + 6b

Combine like terms: 24 + 16 = 40
12 + 8b = 40 + 6b

Solving
12 + 8b = 40 + 6b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-6b' to each side of the equation.
12 + 8b + -6b = 40 + 6b + -6b

Combine like terms: 8b + -6b = 2b
12 + 2b = 40 + 6b + -6b

Combine like terms: 6b + -6b = 0
12 + 2b = 40 + 0
12 + 2b = 40

Add '-12' to each side of the equation.
12 + -12 + 2b = 40 + -12

Combine like terms: 12 + -12 = 0
0 + 2b = 40 + -12
2b = 40 + -12

Combine like terms: 40 + -12 = 28
2b = 28

Divide each side by '2'.
b = 14

Simplifying
b = 14

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