8(b+1)+4=3(2b-8)+b

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Solution for 8(b+1)+4=3(2b-8)+b equation: 



8(b+1)+4=3(2b-8)+b

We move all terms to the left:

8(b+1)+4-(3(2b-8)+b)=0

We multiply parentheses

8b-(3(2b-8)+b)+8+4=0



We calculate terms in parentheses: -(3(2b-8)+b), so:

3(2b-8)+b

We add all the numbers together, and all the variables

b+3(2b-8)

We multiply parentheses

b+6b-24

We add all the numbers together, and all the variables

7b-24

Back to the equation:

-(7b-24)



We add all the numbers together, and all the variables

8b-(7b-24)+12=0

We get rid of parentheses

8b-7b+24+12=0

We add all the numbers together, and all the variables

b+36=0

We move all terms containing b to the left, all other terms to the right

b=-36

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