8(b+1)+7=3(2b-8)-6

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Solution for 8(b+1)+7=3(2b-8)-6 equation: 



8(b+1)+7=3(2b-8)-6

We move all terms to the left:

8(b+1)+7-(3(2b-8)-6)=0

We multiply parentheses

8b-(3(2b-8)-6)+8+7=0



We calculate terms in parentheses: -(3(2b-8)-6), so:

3(2b-8)-6

We multiply parentheses

6b-24-6

We add all the numbers together, and all the variables

6b-30

Back to the equation:

-(6b-30)



We add all the numbers together, and all the variables

8b-(6b-30)+15=0

We get rid of parentheses

8b-6b+30+15=0

We add all the numbers together, and all the variables

2b+45=0

We move all terms containing b to the left, all other terms to the right

2b=-45

b=-45/2

b=-22+1/2

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