8(b+1)=-3(2+b)

Solution for 8(b+1)=-3(2+b) equation:

8(b+1)=-3(2+b)

We move all terms to the left:

8(b+1)-(-3(2+b))=0

We add all the numbers together, and all the variables

8(b+1)-(-3(b+2))=0

We multiply parentheses

8b-(-3(b+2))+8=0


We calculate terms in parentheses: -(-3(b+2)), so:

-3(b+2)

We multiply parentheses

-3b-6

Back to the equation:

-(-3b-6)


We get rid of parentheses

8b+3b+6+8=0

We add all the numbers together, and all the variables

11b+14=0

We move all terms containing b to the left, all other terms to the right

11b=-14

b=-14/11

b=-1+3/11