8(b+1)=3(2b-7)-16

Solution for 8(b+1)=3(2b-7)-16 equation:

8(b+1)=3(2b-7)-16

We move all terms to the left:

8(b+1)-(3(2b-7)-16)=0

We multiply parentheses

8b-(3(2b-7)-16)+8=0


We calculate terms in parentheses: -(3(2b-7)-16), so:

3(2b-7)-16

We multiply parentheses

6b-21-16

We add all the numbers together, and all the variables

6b-37

Back to the equation:

-(6b-37)


We get rid of parentheses

8b-6b+37+8=0

We add all the numbers together, and all the variables

2b+45=0

We move all terms containing b to the left, all other terms to the right

2b=-45

b=-45/2

b=-22+1/2