8(b+1)=3(2b-8)-16

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Solution for 8(b+1)=3(2b-8)-16 equation: 


Simplifying
8(b + 1) = 3(2b + -8) + -16

Reorder the terms:
8(1 + b) = 3(2b + -8) + -16
(1 * 8 + b * 8) = 3(2b + -8) + -16
(8 + 8b) = 3(2b + -8) + -16

Reorder the terms:
8 + 8b = 3(-8 + 2b) + -16
8 + 8b = (-8 * 3 + 2b * 3) + -16
8 + 8b = (-24 + 6b) + -16

Reorder the terms:
8 + 8b = -24 + -16 + 6b

Combine like terms: -24 + -16 = -40
8 + 8b = -40 + 6b

Solving
8 + 8b = -40 + 6b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-6b' to each side of the equation.
8 + 8b + -6b = -40 + 6b + -6b

Combine like terms: 8b + -6b = 2b
8 + 2b = -40 + 6b + -6b

Combine like terms: 6b + -6b = 0
8 + 2b = -40 + 0
8 + 2b = -40

Add '-8' to each side of the equation.
8 + -8 + 2b = -40 + -8

Combine like terms: 8 + -8 = 0
0 + 2b = -40 + -8
2b = -40 + -8

Combine like terms: -40 + -8 = -48
2b = -48

Divide each side by '2'.
b = -24

Simplifying
b = -24

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