8(b+1)=3(2b-8)-20

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Solution for 8(b+1)=3(2b-8)-20 equation: 



8(b+1)=3(2b-8)-20

We move all terms to the left:

8(b+1)-(3(2b-8)-20)=0

We multiply parentheses

8b-(3(2b-8)-20)+8=0



We calculate terms in parentheses: -(3(2b-8)-20), so:

3(2b-8)-20

We multiply parentheses

6b-24-20

We add all the numbers together, and all the variables

6b-44

Back to the equation:

-(6b-44)



We get rid of parentheses

8b-6b+44+8=0

We add all the numbers together, and all the variables

2b+52=0

We move all terms containing b to the left, all other terms to the right

2b=-52

b=-52/2

b=-26

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