8(b+1)=6(8+2b)

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Solution for 8(b+1)=6(8+2b) equation:


Simplifying
8(b + 1) = 6(8 + 2b)

Reorder the terms:
8(1 + b) = 6(8 + 2b)
(1 * 8 + b * 8) = 6(8 + 2b)
(8 + 8b) = 6(8 + 2b)
8 + 8b = (8 * 6 + 2b * 6)
8 + 8b = (48 + 12b)

Solving
8 + 8b = 48 + 12b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-12b' to each side of the equation.
8 + 8b + -12b = 48 + 12b + -12b

Combine like terms: 8b + -12b = -4b
8 + -4b = 48 + 12b + -12b

Combine like terms: 12b + -12b = 0
8 + -4b = 48 + 0
8 + -4b = 48

Add '-8' to each side of the equation.
8 + -8 + -4b = 48 + -8

Combine like terms: 8 + -8 = 0
0 + -4b = 48 + -8
-4b = 48 + -8

Combine like terms: 48 + -8 = 40
-4b = 40

Divide each side by '-4'.
b = -10

Simplifying
b = -10

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