8(b+1+)4=3(2b-8)-16

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Solution for 8(b+1+)4=3(2b-8)-16 equation: 



8(b+1+)4=3(2b-8)-16

We move all terms to the left:

8(b+1+)4-(3(2b-8)-16)=0

We add all the numbers together, and all the variables

8(+b)4-(3(2b-8)-16)=0

We multiply parentheses

32b-(3(2b-8)-16)=0



We calculate terms in parentheses: -(3(2b-8)-16), so:

3(2b-8)-16

We multiply parentheses

6b-24-16

We add all the numbers together, and all the variables

6b-40

Back to the equation:

-(6b-40)



We get rid of parentheses

32b-6b+40=0

We add all the numbers together, and all the variables

26b+40=0

We move all terms containing b to the left, all other terms to the right

26b=-40

b=-40/26

b=-1+7/13

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