8(b+2)-4(b-5)=b+12

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Solution for 8(b+2)-4(b-5)=b+12 equation:


Simplifying
8(b + 2) + -4(b + -5) = b + 12

Reorder the terms:
8(2 + b) + -4(b + -5) = b + 12
(2 * 8 + b * 8) + -4(b + -5) = b + 12
(16 + 8b) + -4(b + -5) = b + 12

Reorder the terms:
16 + 8b + -4(-5 + b) = b + 12
16 + 8b + (-5 * -4 + b * -4) = b + 12
16 + 8b + (20 + -4b) = b + 12

Reorder the terms:
16 + 20 + 8b + -4b = b + 12

Combine like terms: 16 + 20 = 36
36 + 8b + -4b = b + 12

Combine like terms: 8b + -4b = 4b
36 + 4b = b + 12

Reorder the terms:
36 + 4b = 12 + b

Solving
36 + 4b = 12 + b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-1b' to each side of the equation.
36 + 4b + -1b = 12 + b + -1b

Combine like terms: 4b + -1b = 3b
36 + 3b = 12 + b + -1b

Combine like terms: b + -1b = 0
36 + 3b = 12 + 0
36 + 3b = 12

Add '-36' to each side of the equation.
36 + -36 + 3b = 12 + -36

Combine like terms: 36 + -36 = 0
0 + 3b = 12 + -36
3b = 12 + -36

Combine like terms: 12 + -36 = -24
3b = -24

Divide each side by '3'.
b = -8

Simplifying
b = -8

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