8(b+3)-4(b+4)=12

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Solution for 8(b+3)-4(b+4)=12 equation: 



8(b+3)-4(b+4)=12

We move all terms to the left:

8(b+3)-4(b+4)-(12)=0

We multiply parentheses

8b-4b+24-16-12=0

We add all the numbers together, and all the variables

4b-4=0

We move all terms containing b to the left, all other terms to the right

4b=4

b=4/4

b=1

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