8(b+4)-7b=4b+4(1+b)

Solution for 8(b+4)-7b=4b+4(1+b) equation:

8(b+4)-7b=4b+4(1+b)

We move all terms to the left:

8(b+4)-7b-(4b+4(1+b))=0

We add all the numbers together, and all the variables

8(b+4)-7b-(4b+4(b+1))=0

We add all the numbers together, and all the variables

-7b+8(b+4)-(4b+4(b+1))=0

We multiply parentheses

-7b+8b-(4b+4(b+1))+32=0


We calculate terms in parentheses: -(4b+4(b+1)), so:

4b+4(b+1)

We multiply parentheses

4b+4b+4

We add all the numbers together, and all the variables

8b+4

Back to the equation:

-(8b+4)


We add all the numbers together, and all the variables

b-(8b+4)+32=0

We get rid of parentheses

b-8b-4+32=0

We add all the numbers together, and all the variables

-7b+28=0

We move all terms containing b to the left, all other terms to the right

-7b=-28

b=-28/-7

b=+4