8(b+4)=4(-2+3b)

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Solution for 8(b+4)=4(-2+3b) equation: 



8(b+4)=4(-2+3b)

We move all terms to the left:

8(b+4)-(4(-2+3b))=0

We add all the numbers together, and all the variables

8(b+4)-(4(3b-2))=0

We multiply parentheses

8b-(4(3b-2))+32=0



We calculate terms in parentheses: -(4(3b-2)), so:

4(3b-2)

We multiply parentheses

12b-8

Back to the equation:

-(12b-8)



We get rid of parentheses

8b-12b+8+32=0

We add all the numbers together, and all the variables

-4b+40=0

We move all terms containing b to the left, all other terms to the right

-4b=-40

b=-40/-4

b=+10

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