8(b-2)=4(12+b)

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Solution for 8(b-2)=4(12+b) equation: 



8(b-2)=4(12+b)

We move all terms to the left:

8(b-2)-(4(12+b))=0

We add all the numbers together, and all the variables

8(b-2)-(4(b+12))=0

We multiply parentheses

8b-(4(b+12))-16=0



We calculate terms in parentheses: -(4(b+12)), so:

4(b+12)

We multiply parentheses

4b+48

Back to the equation:

-(4b+48)



We get rid of parentheses

8b-4b-48-16=0

We add all the numbers together, and all the variables

4b-64=0

We move all terms containing b to the left, all other terms to the right

4b=64

b=64/4

b=16

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