8(b-3)+5=3(b-1)

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Solution for 8(b-3)+5=3(b-1) equation:


Simplifying
8(b + -3) + 5 = 3(b + -1)

Reorder the terms:
8(-3 + b) + 5 = 3(b + -1)
(-3 * 8 + b * 8) + 5 = 3(b + -1)
(-24 + 8b) + 5 = 3(b + -1)

Reorder the terms:
-24 + 5 + 8b = 3(b + -1)

Combine like terms: -24 + 5 = -19
-19 + 8b = 3(b + -1)

Reorder the terms:
-19 + 8b = 3(-1 + b)
-19 + 8b = (-1 * 3 + b * 3)
-19 + 8b = (-3 + 3b)

Solving
-19 + 8b = -3 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
-19 + 8b + -3b = -3 + 3b + -3b

Combine like terms: 8b + -3b = 5b
-19 + 5b = -3 + 3b + -3b

Combine like terms: 3b + -3b = 0
-19 + 5b = -3 + 0
-19 + 5b = -3

Add '19' to each side of the equation.
-19 + 19 + 5b = -3 + 19

Combine like terms: -19 + 19 = 0
0 + 5b = -3 + 19
5b = -3 + 19

Combine like terms: -3 + 19 = 16
5b = 16

Divide each side by '5'.
b = 3.2

Simplifying
b = 3.2

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