8(b-4)+6=4(b+1)+4b-30

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Solution for 8(b-4)+6=4(b+1)+4b-30 equation: 



8(b-4)+6=4(b+1)+4b-30

We move all terms to the left:

8(b-4)+6-(4(b+1)+4b-30)=0

We multiply parentheses

8b-(4(b+1)+4b-30)-32+6=0



We calculate terms in parentheses: -(4(b+1)+4b-30), so:

4(b+1)+4b-30

We add all the numbers together, and all the variables

4b+4(b+1)-30

We multiply parentheses

4b+4b+4-30

We add all the numbers together, and all the variables

8b-26

Back to the equation:

-(8b-26)



We add all the numbers together, and all the variables

8b-(8b-26)-26=0

We get rid of parentheses

8b-8b+26-26=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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