8(b-7)+8=4(2b-8)-16

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Solution for 8(b-7)+8=4(2b-8)-16 equation: 



8(b-7)+8=4(2b-8)-16

We move all terms to the left:

8(b-7)+8-(4(2b-8)-16)=0

We multiply parentheses

8b-(4(2b-8)-16)-56+8=0



We calculate terms in parentheses: -(4(2b-8)-16), so:

4(2b-8)-16

We multiply parentheses

8b-32-16

We add all the numbers together, and all the variables

8b-48

Back to the equation:

-(8b-48)



We add all the numbers together, and all the variables

8b-(8b-48)-48=0

We get rid of parentheses

8b-8b+48-48=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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