8(b-7)=-40+4b

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Solution for 8(b-7)=-40+4b equation: 



8(b-7)=-40+4b

We move all terms to the left:

8(b-7)-(-40+4b)=0

We add all the numbers together, and all the variables

8(b-7)-(4b-40)=0

We multiply parentheses

8b-(4b-40)-56=0

We get rid of parentheses

8b-4b+40-56=0

We add all the numbers together, and all the variables

4b-16=0

We move all terms containing b to the left, all other terms to the right

4b=16

b=16/4

b=4

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