8(b-7)=3(b-2)

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Solution for 8(b-7)=3(b-2) equation:



8(b-7)=3(b-2)
We move all terms to the left:
8(b-7)-(3(b-2))=0
We multiply parentheses
8b-(3(b-2))-56=0
We calculate terms in parentheses: -(3(b-2)), so:
3(b-2)
We multiply parentheses
3b-6
Back to the equation:
-(3b-6)
We get rid of parentheses
8b-3b+6-56=0
We add all the numbers together, and all the variables
5b-50=0
We move all terms containing b to the left, all other terms to the right
5b=50
b=50/5
b=10

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