8(b-7)=3(b-2)

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Solution for 8(b-7)=3(b-2) equation: 



8(b-7)=3(b-2)

We move all terms to the left:

8(b-7)-(3(b-2))=0

We multiply parentheses

8b-(3(b-2))-56=0



We calculate terms in parentheses: -(3(b-2)), so:

3(b-2)

We multiply parentheses

3b-6

Back to the equation:

-(3b-6)



We get rid of parentheses

8b-3b+6-56=0

We add all the numbers together, and all the variables

5b-50=0

We move all terms containing b to the left, all other terms to the right

5b=50

b=50/5

b=10

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