8(b-c)+2c-3b=0

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Solution for 8(b-c)+2c-3b=0 equation:


Simplifying
8(b + -1c) + 2c + -3b = 0
(b * 8 + -1c * 8) + 2c + -3b = 0
(8b + -8c) + 2c + -3b = 0

Reorder the terms:
8b + -3b + -8c + 2c = 0

Combine like terms: 8b + -3b = 5b
5b + -8c + 2c = 0

Combine like terms: -8c + 2c = -6c
5b + -6c = 0

Solving
5b + -6c = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '6c' to each side of the equation.
5b + -6c + 6c = 0 + 6c

Combine like terms: -6c + 6c = 0
5b + 0 = 0 + 6c
5b = 0 + 6c
Remove the zero:
5b = 6c

Divide each side by '5'.
b = 1.2c

Simplifying
b = 1.2c

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