8(c+1)=2(c-2)

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Solution for 8(c+1)=2(c-2) equation:


Simplifying
8(c + 1) = 2(c + -2)

Reorder the terms:
8(1 + c) = 2(c + -2)
(1 * 8 + c * 8) = 2(c + -2)
(8 + 8c) = 2(c + -2)

Reorder the terms:
8 + 8c = 2(-2 + c)
8 + 8c = (-2 * 2 + c * 2)
8 + 8c = (-4 + 2c)

Solving
8 + 8c = -4 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
8 + 8c + -2c = -4 + 2c + -2c

Combine like terms: 8c + -2c = 6c
8 + 6c = -4 + 2c + -2c

Combine like terms: 2c + -2c = 0
8 + 6c = -4 + 0
8 + 6c = -4

Add '-8' to each side of the equation.
8 + -8 + 6c = -4 + -8

Combine like terms: 8 + -8 = 0
0 + 6c = -4 + -8
6c = -4 + -8

Combine like terms: -4 + -8 = -12
6c = -12

Divide each side by '6'.
c = -2

Simplifying
c = -2

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