8(c+1)=4c-8

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Solution for 8(c+1)=4c-8 equation: 



8(c+1)=4c-8

We move all terms to the left:

8(c+1)-(4c-8)=0

We multiply parentheses

8c-(4c-8)+8=0

We get rid of parentheses

8c-4c+8+8=0

We add all the numbers together, and all the variables

4c+16=0

We move all terms containing c to the left, all other terms to the right

4c=-16

c=-16/4

c=-4

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