8(c+1)=4c-8

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Solution for 8(c+1)=4c-8 equation:



8(c+1)=4c-8
We move all terms to the left:
8(c+1)-(4c-8)=0
We multiply parentheses
8c-(4c-8)+8=0
We get rid of parentheses
8c-4c+8+8=0
We add all the numbers together, and all the variables
4c+16=0
We move all terms containing c to the left, all other terms to the right
4c=-16
c=-16/4
c=-4

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