8(c+1)whenc=4

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Solution for 8(c+1)whenc=4 equation: 


Simplifying
8(c + 1) * whenc = 4

Reorder the terms:
8(1 + c) * whenc = 4

Reorder the terms for easier multiplication:
8cehnw(1 + c) = 4
(1 * 8cehnw + c * 8cehnw) = 4
(8cehnw + 8c2ehnw) = 4

Solving
8cehnw + 8c2ehnw = 4

Solving for variable 'c'.

Reorder the terms:
-4 + 8cehnw + 8c2ehnw = 4 + -4

Combine like terms: 4 + -4 = 0
-4 + 8cehnw + 8c2ehnw = 0

Factor out the Greatest Common Factor (GCF), '4'.
4(-1 + 2cehnw + 2c2ehnw) = 0

Ignore the factor 4.

Subproblem 1
Set the factor '(-1 + 2cehnw + 2c2ehnw)' equal to zero and attempt to solve:

Simplifying
-1 + 2cehnw + 2c2ehnw = 0

Solving
-1 + 2cehnw + 2c2ehnw = 0

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

The solution to this equation could not be determined.

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