8(c+2)-2(2c-1)=2(6c+)

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Solution for 8(c+2)-2(2c-1)=2(6c+) equation: 



8(c+2)-2(2c-1)=2(6c+)

We move all terms to the left:

8(c+2)-2(2c-1)-(2(6c+))=0

We add all the numbers together, and all the variables

8(c+2)-2(2c-1)-(2(+6c))=0

We multiply parentheses

8c-4c-(2(+6c))+16+2=0



We calculate terms in parentheses: -(2(+6c)), so:

2(+6c)

We multiply parentheses

12c

Back to the equation:

-(12c)



We add all the numbers together, and all the variables

-8c+18=0

We move all terms containing c to the left, all other terms to the right

-8c=-18

c=-18/-8

c=2+1/4

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