8(c+2)=2(8+c)

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Solution for 8(c+2)=2(8+c) equation: 



8(c+2)=2(8+c)

We move all terms to the left:

8(c+2)-(2(8+c))=0

We add all the numbers together, and all the variables

8(c+2)-(2(c+8))=0

We multiply parentheses

8c-(2(c+8))+16=0



We calculate terms in parentheses: -(2(c+8)), so:

2(c+8)

We multiply parentheses

2c+16

Back to the equation:

-(2c+16)



We get rid of parentheses

8c-2c-16+16=0

We add all the numbers together, and all the variables

6c=0

c=0/6

c=0

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