8(c-12)=6(2c-16)-4c

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Solution for 8(c-12)=6(2c-16)-4c equation: 



8(c-12)=6(2c-16)-4c

We move all terms to the left:

8(c-12)-(6(2c-16)-4c)=0

We multiply parentheses

8c-(6(2c-16)-4c)-96=0



We calculate terms in parentheses: -(6(2c-16)-4c), so:

6(2c-16)-4c

We add all the numbers together, and all the variables

-4c+6(2c-16)

We multiply parentheses

-4c+12c-96

We add all the numbers together, and all the variables

8c-96

Back to the equation:

-(8c-96)



We get rid of parentheses

8c-8c+96-96=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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