8(c-12)=8(2c-12)-c

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Solution for 8(c-12)=8(2c-12)-c equation: 



8(c-12)=8(2c-12)-c

We move all terms to the left:

8(c-12)-(8(2c-12)-c)=0

We multiply parentheses

8c-(8(2c-12)-c)-96=0



We calculate terms in parentheses: -(8(2c-12)-c), so:

8(2c-12)-c

We add all the numbers together, and all the variables

-1c+8(2c-12)

We multiply parentheses

-1c+16c-96

We add all the numbers together, and all the variables

15c-96

Back to the equation:

-(15c-96)



We get rid of parentheses

8c-15c+96-96=0

We add all the numbers together, and all the variables

-7c=0

c=0/-7

c=0

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