8(c-3)+5=2+c-21

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Solution for 8(c-3)+5=2+c-21 equation:


Simplifying
8(c + -3) + 5 = 2 + c + -21

Reorder the terms:
8(-3 + c) + 5 = 2 + c + -21
(-3 * 8 + c * 8) + 5 = 2 + c + -21
(-24 + 8c) + 5 = 2 + c + -21

Reorder the terms:
-24 + 5 + 8c = 2 + c + -21

Combine like terms: -24 + 5 = -19
-19 + 8c = 2 + c + -21

Reorder the terms:
-19 + 8c = 2 + -21 + c

Combine like terms: 2 + -21 = -19
-19 + 8c = -19 + c

Add '19' to each side of the equation.
-19 + 19 + 8c = -19 + 19 + c

Combine like terms: -19 + 19 = 0
0 + 8c = -19 + 19 + c
8c = -19 + 19 + c

Combine like terms: -19 + 19 = 0
8c = 0 + c
8c = c

Solving
8c = c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
8c + -1c = c + -1c

Combine like terms: 8c + -1c = 7c
7c = c + -1c

Combine like terms: c + -1c = 0
7c = 0

Divide each side by '7'.
c = 0

Simplifying
c = 0

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