8(c-5)=4(3c-3)

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Solution for 8(c-5)=4(3c-3) equation: 



8(c-5)=4(3c-3)

We move all terms to the left:

8(c-5)-(4(3c-3))=0

We multiply parentheses

8c-(4(3c-3))-40=0



We calculate terms in parentheses: -(4(3c-3)), so:

4(3c-3)

We multiply parentheses

12c-12

Back to the equation:

-(12c-12)



We get rid of parentheses

8c-12c+12-40=0

We add all the numbers together, and all the variables

-4c-28=0

We move all terms containing c to the left, all other terms to the right

-4c=28

c=28/-4

c=-7

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