8(c-6)=3(3c+10)

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Solution for 8(c-6)=3(3c+10) equation: 



8(c-6)=3(3c+10)

We move all terms to the left:

8(c-6)-(3(3c+10))=0

We multiply parentheses

8c-(3(3c+10))-48=0



We calculate terms in parentheses: -(3(3c+10)), so:

3(3c+10)

We multiply parentheses

9c+30

Back to the equation:

-(9c+30)



We get rid of parentheses

8c-9c-30-48=0

We add all the numbers together, and all the variables

-1c-78=0

We move all terms containing c to the left, all other terms to the right

-c=78

c=78/-1

c=-78

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