8(c-6)=3(c+10)

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Solution for 8(c-6)=3(c+10) equation: 



8(c-6)=3(c+10)

We move all terms to the left:

8(c-6)-(3(c+10))=0

We multiply parentheses

8c-(3(c+10))-48=0



We calculate terms in parentheses: -(3(c+10)), so:

3(c+10)

We multiply parentheses

3c+30

Back to the equation:

-(3c+30)



We get rid of parentheses

8c-3c-30-48=0

We add all the numbers together, and all the variables

5c-78=0

We move all terms containing c to the left, all other terms to the right

5c=78

c=78/5

c=15+3/5

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