8(c-9)=6(2c-12)-4c=

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Solution for 8(c-9)=6(2c-12)-4c= equation: 



8(c-9)=6(2c-12)-4c=

We move all terms to the left:

8(c-9)-(6(2c-12)-4c)=0

We multiply parentheses

8c-(6(2c-12)-4c)-72=0



We calculate terms in parentheses: -(6(2c-12)-4c), so:

6(2c-12)-4c

We add all the numbers together, and all the variables

-4c+6(2c-12)

We multiply parentheses

-4c+12c-72

We add all the numbers together, and all the variables

8c-72

Back to the equation:

-(8c-72)



We get rid of parentheses

8c-8c+72-72=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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