8(c-9)=6(2c-12-4c)

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Solution for 8(c-9)=6(2c-12-4c) equation:


Simplifying
8(c + -9) = 6(2c + -12 + -4c)

Reorder the terms:
8(-9 + c) = 6(2c + -12 + -4c)
(-9 * 8 + c * 8) = 6(2c + -12 + -4c)
(-72 + 8c) = 6(2c + -12 + -4c)

Reorder the terms:
-72 + 8c = 6(-12 + 2c + -4c)

Combine like terms: 2c + -4c = -2c
-72 + 8c = 6(-12 + -2c)
-72 + 8c = (-12 * 6 + -2c * 6)
-72 + 8c = (-72 + -12c)

Add '72' to each side of the equation.
-72 + 72 + 8c = -72 + 72 + -12c

Combine like terms: -72 + 72 = 0
0 + 8c = -72 + 72 + -12c
8c = -72 + 72 + -12c

Combine like terms: -72 + 72 = 0
8c = 0 + -12c
8c = -12c

Solving
8c = -12c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '12c' to each side of the equation.
8c + 12c = -12c + 12c

Combine like terms: 8c + 12c = 20c
20c = -12c + 12c

Combine like terms: -12c + 12c = 0
20c = 0

Divide each side by '20'.
c = 0.0

Simplifying
c = 0.0

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