8(d+2)-36=2+6(1+d)

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Solution for 8(d+2)-36=2+6(1+d) equation: 



8(d+2)-36=2+6(1+d)

We move all terms to the left:

8(d+2)-36-(2+6(1+d))=0

We add all the numbers together, and all the variables

8(d+2)-(2+6(d+1))-36=0

We multiply parentheses

8d-(2+6(d+1))+16-36=0



We calculate terms in parentheses: -(2+6(d+1)), so:

2+6(d+1)

determiningTheFunctionDomain
6(d+1)+2

We multiply parentheses

6d+6+2

We add all the numbers together, and all the variables

6d+8

Back to the equation:

-(6d+8)



We add all the numbers together, and all the variables

8d-(6d+8)-20=0

We get rid of parentheses

8d-6d-8-20=0

We add all the numbers together, and all the variables

2d-28=0

We move all terms containing d to the left, all other terms to the right

2d=28

d=28/2

d=14

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