8(d+2)=58

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Solution for 8(d+2)=58 equation: 



8(d+2)=58

We move all terms to the left:

8(d+2)-(58)=0

We multiply parentheses

8d+16-58=0

We add all the numbers together, and all the variables

8d-42=0

We move all terms containing d to the left, all other terms to the right

8d=42

d=42/8

d=5+1/4

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