8(d+5)=12d-I

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Solution for 8(d+5)=12d-I equation: 



8(d+5)=12d-

We move all terms to the left:

8(d+5)-(12d-)=0

We add all the numbers together, and all the variables

8(d+5)-(+12d)=0

We multiply parentheses

8d-(+12d)+40=0

We get rid of parentheses

8d-12d+40=0

We add all the numbers together, and all the variables

-4d+40=0

We move all terms containing d to the left, all other terms to the right

-4d=-40

d=-40/-4

d=+10

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