8(d-0)=32

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Solution for 8(d-0)=32 equation: 



8(d-0)=32

We move all terms to the left:

8(d-0)-(32)=0

We add all the numbers together, and all the variables

8(+d)-32=0

We multiply parentheses

8d-32=0

We move all terms containing d to the left, all other terms to the right

8d=32

d=32/8

d=4

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