8(d-1)+17(d-3)=5(4d-4)+5

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Solution for 8(d-1)+17(d-3)=5(4d-4)+5 equation: 



8(d-1)+17(d-3)=5(4d-4)+5

We move all terms to the left:

8(d-1)+17(d-3)-(5(4d-4)+5)=0

We multiply parentheses

8d+17d-(5(4d-4)+5)-8-51=0



We calculate terms in parentheses: -(5(4d-4)+5), so:

5(4d-4)+5

We multiply parentheses

20d-20+5

We add all the numbers together, and all the variables

20d-15

Back to the equation:

-(20d-15)



We add all the numbers together, and all the variables

25d-(20d-15)-59=0

We get rid of parentheses

25d-20d+15-59=0

We add all the numbers together, and all the variables

5d-44=0

We move all terms containing d to the left, all other terms to the right

5d=44

d=44/5

d=8+4/5

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