8(e+1)-5=3(2e-4)-1

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Solution for 8(e+1)-5=3(2e-4)-1 equation: 



8(e+1)-5=3(2e-4)-1

We move all terms to the left:

8(e+1)-5-(3(2e-4)-1)=0

We multiply parentheses

8e-(3(2e-4)-1)+8-5=0



We calculate terms in parentheses: -(3(2e-4)-1), so:

3(2e-4)-1

We multiply parentheses

6e-12-1

We add all the numbers together, and all the variables

6e-13

Back to the equation:

-(6e-13)



We add all the numbers together, and all the variables

8e-(6e-13)+3=0

We get rid of parentheses

8e-6e+13+3=0

We add all the numbers together, and all the variables

2e+16=0

We move all terms containing e to the left, all other terms to the right

2e=-16

e=-16/2

e=-8

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