8(j-2)-3(1-j)=9(j+2)+1

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Solution for 8(j-2)-3(1-j)=9(j+2)+1 equation: 



8(j-2)-3(1-j)=9(j+2)+1

We move all terms to the left:

8(j-2)-3(1-j)-(9(j+2)+1)=0

We add all the numbers together, and all the variables

8(j-2)-3(-1j+1)-(9(j+2)+1)=0

We multiply parentheses

8j+3j-(9(j+2)+1)-16-3=0



We calculate terms in parentheses: -(9(j+2)+1), so:

9(j+2)+1

We multiply parentheses

9j+18+1

We add all the numbers together, and all the variables

9j+19

Back to the equation:

-(9j+19)



We add all the numbers together, and all the variables

11j-(9j+19)-19=0

We get rid of parentheses

11j-9j-19-19=0

We add all the numbers together, and all the variables

2j-38=0

We move all terms containing j to the left, all other terms to the right

2j=38

j=38/2

j=19

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