8(j-3)-6j=100

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Solution for 8(j-3)-6j=100 equation:



8(j-3)-6j=100
We move all terms to the left:
8(j-3)-6j-(100)=0
We add all the numbers together, and all the variables
-6j+8(j-3)-100=0
We multiply parentheses
-6j+8j-24-100=0
We add all the numbers together, and all the variables
2j-124=0
We move all terms containing j to the left, all other terms to the right
2j=124
j=124/2
j=62

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